Parity / Checksum / Encryption Challenge

This is a time-limited challenge open to everybody.

Challenge Details:
- There are 600+ Arrays/Strings. Each consists of 17 Char/Digit.
- The first 14 digits are all known strictly integers.
- Last 3 characters (15th, 16th, and 17th) can be alphanumeric (Ex: A, B, C, a, b, c, 1, 2, 3....etc)
- The last 3 characters are parity check for the first 14 digits.

Hint: the second parity character (16th) is related to the sum of the even indexed digits except 6th on (i.e. sum of 2nd, 4th, 8th, 10th, 12th, and 14th determines the 2nd parity/16th digit).

Here is a data sample of 10 examples:

6 4 5 7 1 3 8 0 1 1 5 0 0 1 A m 0
6 4 5 3 9 7 8 0 1 1 5 0 0 1 D p A
6 4 0 0 6 9 8 0 3 1 5 0 0 1 I s a
5 1 0 9 9 3 5 1 1 1 7 5 0 3 q M b
6 4 0 8 4 7 8 0 1 1 5 0 0 1 u 3 e
6 4 0 5 0 5 8 0 3 1 5 0 0 1 B 2 F
6 4 0 2 6 5 8 0 3 1 5 0 0 1 I d I
6 4 0 3 2 1 8 0 3 1 5 0 0 1 S g K
6 4 0 0 8 3 8 0 3 1 5 0 0 1 Z s k
5 3 0 8 2 3 5 2 3 1 5 5 0 3 C W L


IMPORTANT:
- The challenge is time limited: 72hrs from the time you get the full data.
- The challenge is All or None i.e. you get fully paid only if you solve it. No partial payments or milestones.
- The solution should be given in form of excel sheet where the determined formula fits all the given data with no exception. For example:
* if the sum of index 1,3,and 5 is 8 then the 1st parity digit(15th) should be "S"
* if the sum of index 2,4,,8,10,12,and 14 is 32 then the 2nd parity digit(16th) should be "u"
* if the sum of index 1,3,5,7,9and 11 is 23 then the 3rd parity digit(17th) should be "9"

Goodluck